0=w^2+9w-3

Solution for 0=w^2+9w-3 equation:

0=w^2+9w-3

We move all terms to the left:

0-(w^2+9w-3)=0

We add all the numbers together, and all the variables

-(w^2+9w-3)=0

We get rid of parentheses

-w^2-9w+3=0

We add all the numbers together, and all the variables

-1w^2-9w+3=0

a = -1; b = -9; c = +3;
Δ = b2-4ac
Δ = -92-4·(-1)·3
Δ = 93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{93}}{2*-1}=\frac{9-\sqrt{93}}{-2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{93}}{2*-1}=\frac{9+\sqrt{93}}{-2}
$